A silver ornament of mass 'm' gram is polished with gold
Mass of silver $$=frac {m}{108}$$ g Mass of gold$$=frac {m}{100}$$ g Number of atoms of silver$$=dfrac{Mass}{Atomic,Mass}times N_A$$ $$= frac {m}{108} times N_A$$ Number of atoms of gold$$= frac {m}{100 times 197} times N_A$$ The ratio of number of atoms of gold to silver = Au: Ag $$= frac {m}{100 times 197} times N_A : frac …
